Bug #74333 | create table output not accepted for virtual columns | ||
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Submitted: | 11 Oct 2014 18:46 | Modified: | 15 Dec 2014 15:33 |
Reporter: | Daniël van Eeden (OCA) | Email Updates: | |
Status: | Closed | Impact on me: | |
Category: | MySQL Server: Parser | Severity: | S3 (Non-critical) |
Version: | 5.7.5-labs-preview | OS: | Any |
Assigned to: | CPU Architecture: | Any | |
Tags: | column, generated, virtual |
[11 Oct 2014 18:46]
Daniël van Eeden
[13 Oct 2014 7:44]
MySQL Verification Team
Hello Daniël, Thank you for the report and test case. Thanks, Umesh
[13 Oct 2014 7:44]
MySQL Verification Team
// mysql> show variables like '%version%'; +-------------------------+------------------------------+ | Variable_name | Value | +-------------------------+------------------------------+ | innodb_version | 5.7.5 | | protocol_version | 10 | | slave_type_conversions | | | version | 5.7.5-labs-preview-log | | version_comment | MySQL Community Server (GPL) | | version_compile_machine | x86_64 | | version_compile_os | linux-el6 | +-------------------------+------------------------------+ 7 rows in set (0.00 sec) mysql> create table t1 (id int, idx2 int as (id * 2)); Query OK, 0 rows affected (0.03 sec) mysql> show create table t1\G *************************** 1. row *************************** Table: t1 Create Table: CREATE TABLE `t1` ( `id` int(11) DEFAULT NULL, `idx2` VIRTUAL int(11) AS (id * 2) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 1 row in set (0.00 sec) mysql> drop table t1; Query OK, 0 rows affected (0.01 sec) mysql> mysql> CREATE TABLE `t1` ( -> `id` int(11) DEFAULT NULL, -> `idx2` VIRTUAL int(11) AS (id * 2) -> ) ENGINE=InnoDB DEFAULT CHARSET=latin1; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VIRTUAL int(11) AS (id * 2) ) ENGINE=InnoDB DEFAULT CHARSET=latin1' at line 3
[15 Dec 2014 15:33]
Erlend Dahl
This has now been fixed on the feature tree for WL#411.