| Bug #71949 | JSON_VALID does not reject invalid documents | ||
|---|---|---|---|
| Submitted: | 5 Mar 2014 20:29 | Modified: | 12 Mar 2014 18:12 |
| Reporter: | Sveta Smirnova | Email Updates: | |
| Status: | Closed | Impact on me: | |
| Category: | MySQL Server: JSON User-defined function ( UDF ) | Severity: | S3 (Non-critical) |
| Version: | 0.3.1 | OS: | Any |
| Assigned to: | CPU Architecture: | Any | |
[12 Mar 2014 18:12]
Sveta Smirnova
Posted by developer: Fixed in version 0.3.1
Description: If there is no separator between array elements JSON_VALID still considers such documents as valid. How to repeat: select json_valid('[1, 2 3]'); json_valid('[1, 2 3]') 1 select json_valid('{"foo": "bar" "baz": "ban"}'); json_valid('{"foo": "bar" "baz": "ban"}') 1 Suggested fix: Should return 0 in both cases.