| Bug #5765 | error in mysql_fetch_field() and mysql_fetch_fields() | ||
|---|---|---|---|
| Submitted: | 27 Sep 2004 15:23 | Modified: | 6 Nov 2004 11:08 |
| Reporter: | Salvatore Sorrentino | Email Updates: | |
| Status: | No Feedback | Impact on me: | |
| Category: | MySQL Server | Severity: | S1 (Critical) |
| Version: | 4.1 | OS: | MacOS (OS X) |
| Assigned to: | Assigned Account | CPU Architecture: | Any |
[6 Oct 2004 11:08]
Hartmut Holzgraefe
Can you please provide a complete compilable example that shows the problem and make sure that this is not a problem in your code?
[14 Feb 2005 22:54]
Bugs System
No feedback was provided for this bug for over a month, so it is being suspended automatically. If you are able to provide the information that was originally requested, please do so and change the status of the bug back to "Open".

Description: When using mysql_fetch_fields(), the the client lib skips every other field in the array, eventually causing a memory access error. When using mysql_fetch_field() the field_type does not report correctly. How to repeat: //if (fieldNames) [fieldNames release]; unsigned cnt = mysql_num_fields(res); field = mysql_fetch_fields(res); unsigned j; myFields = malloc_zone_malloc(mallocZone, sizeof(int) * cnt); myFields = malloc(sizeof(int) * cnt); //unsigned cntr = 0; //fieldNames = [[NSMutableArray alloc] initWithCapacity:cnt]; for(i = 0; i < cnt; i++) { //NSString *name = [[NSString alloc] initWithCString:field[i].name]; myFields[i] = field[i].type; printf("Field %u = %s, type = %i" , i, field[i].name, myFields[i]); //[fieldNames addObject:name]; //[name release]; } Suggested fix: ??