Bug #37475 | c example code for mysql_stmt_execute() and mysql_stmt_fetch() | ||
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Submitted: | 18 Jun 2008 11:21 | Modified: | 14 Dec 2008 20:51 |
Reporter: | Robert Grabein | Email Updates: | |
Status: | No Feedback | Impact on me: | |
Category: | MySQL Server: C API (client library) | Severity: | S3 (Non-critical) |
Version: | mysql 5.0.51b-win32 | OS: | Windows |
Assigned to: | Assigned Account | CPU Architecture: | Any |
[18 Jun 2008 11:21]
Robert Grabein
[18 Jun 2008 11:25]
Susanne Ebrecht
Many thanks for writing a bug report. Please can you provide a short test here.
[14 Nov 2008 20:51]
MySQL Verification Team
Thank you for the bug report. I tried the sample code with the below changes: /* #include "stdafx.h" #include <cstdio> #include <conio.h> #include <string.h> #include <winsock.h> #include "mysql.h" #pragma comment(lib,"libmysql") */ #include <my_global.h> #include <m_string.h> #include <conio.h> #include <ctype.h> #include "mysql.h" //using namespace System; int main() { MYSQL *mysql; mysql = mysql_init(NULL); mysql_real_connect(mysql, "localhost", "root", "", "test", 3500, NULL, 0); I linked against the static client library mysqlclient.lib and I got the below output: C:\temp>MySQLbug37475 prepare, INSERT successful total parameters in INSERT: 3 total affected rows(insert 1): 1 total affected rows(insert 2): 1 and how if (mysql_stmt_close(stmt)) is called again in the exitpoint: I got a crash on your sample. I compiled with VS2003 and with source server 5.0.72. So I don't have idea what it was wrong on your side. Any clues?. Thanks
[15 Dec 2008 0:00]
Bugs System
No feedback was provided for this bug for over a month, so it is being suspended automatically. If you are able to provide the information that was originally requested, please do so and change the status of the bug back to "Open".