| Bug #2288 | libmysqlclient requires -lm in gcc command | ||
|---|---|---|---|
| Submitted: | 5 Jan 2004 9:06 | Modified: | 5 Jan 2004 9:38 |
| Reporter: | Barry Byrne | Email Updates: | |
| Status: | Not a Bug | Impact on me: | |
| Category: | MySQL Server | Severity: | S3 (Non-critical) |
| Version: | 4.0.17 | OS: | sparc Solaris 8 |
| Assigned to: | Dean Ellis | CPU Architecture: | Any |
[5 Jan 2004 9:16]
Dean Ellis
Check mysql_config --libs to see that -lm is specified. If so, this is not a bug.
[5 Jan 2004 9:23]
Barry Byrne
I have now checked mysql_config bash-2.05$ mysql_config --libs -L/usr/local/mysql/lib -lmysqlclient -lposix4 -lcrypt -lgen -lsocket -lnsl -lm (as you predicted) Thanks for your quick response; what part of the documentation have I missed?
[5 Jan 2004 9:26]
Barry Byrne
Rhetorical question! 4.9.11
[5 Jan 2004 9:38]
Dean Ellis
Also 12.1.13 "Building Client Programs", which references this as well. It is easy to overlook.
Description: I installed the binary of 4.0.17 and ran the compilation gcc -o report_listener *.c -lsocket -lnsl -lmysqlclient \ -I/usr/local/mysql/include -L/usr/local/mysql/lib and got the report Undefined first referenced symbol in file floor /usr/local/mysql/lib/libmysqlclient.a(password.o) ld: fatal: Symbol referencing errors. No output written to report_listener collect2: ld returned 1 exit status I changed the compilation line to gcc -o report_listener *.c -lsocket -lnsl -lmysqlclient -lm\ -I/usr/local/mysql/include -L/usr/local/mysql/lib and it worked. How to repeat: It looks as though you have to have some code that invokes password.c in libmysqlclient maybe just if(mysql_real_connect(&mysql, DB_HOST, DB_USER, DB_PASS, DB_NAME, 0, NULL, 0) == NULL) { Suggested fix: Use -lm in the compilation command.