Bug #117417 Creating index causes partitioning failure
| Submitted: | 8 Feb 2025 11:39 | Modified: | 11 Feb 2025 12:37 |
|---|---|---|---|
| Reporter: | Jiyuan Li | Email Updates: | |
| Status: | Not a Bug | Impact on me: | |
| Category: | MySQL Cluster: Cluster (NDB) storage engine | Severity: | S3 (Non-critical) |
| Version: | 9.1.0-cluster | OS: | Ubuntu (22.04) |
| Assigned to: | MySQL Verification Team | CPU Architecture: | x86 |
[11 Feb 2025 12:37]
MySQL Verification Team
We're sorry, but the bug system is not the appropriate forum for asking help on using MySQL products. Your problem is not the result of a bug. For details on getting support for MySQL products see http://www.mysql.com/support/ You can also check our forums (free) at http://forums.mysql.com/ Thank you for your interest in MySQL.
Portions of this website are copyright © 2001, 2002 The PHP Group
Page generated in 0.039 sec. using MySQL 8.4.7-u6-cloud
Timestamp references displayed by the system are UTC.
Content reproduced on this site is the property of the
respective copyright holders.
It is not reviewed in advance
by Oracle and does not necessarily represent the opinion of
Oracle or any other party.
Description: I created a table and created an index on it, then I tried to partition the table but I got an error. How to repeat: CREATE TABLE t0(c0 DECIMAL COLUMN_FORMAT FIXED , c1 DECIMAL PRIMARY KEY NOT NULL UNIQUE COLUMN_FORMAT DEFAULT STORAGE MEMORY) ; CREATE INDEX i1 USING BTREE ON t0((CAST((CAST('Sπ' AS SIGNED)) IS NOT UNKNOWN AS SIGNED))) VISIBLE; INSERT HIGH_PRIORITY IGNORE INTO t0(c1) VALUES(NULL); alter table t0 partition by key() partitions 56;