Bug #8134 Strange behaveor comparing strings which begins with CHAR(31).
Submitted: 25 Jan 2005 16:01 Modified: 3 Feb 2005 22:09
Reporter: Moris Buga
Status: Closed
Category:Server Severity:S3 (Non-critical)
Version:4.1.8 OS:Linux (Linux)
Assigned to: Jim Winstead Target Version:

[25 Jan 2005 16:01] Moris Buga 
Description:
Empty string is equal with any string that begins with CHAR(31).

mysql> SELECT '' = CONCAT(CHAR(31),'ABC'), CONCAT(CHAR(31),'ABC') = '';
+-----------------------------+-----------------------------+
| '' = CONCAT(CHAR(31),'ABC') | CONCAT(CHAR(31),'ABC') = '' |
+-----------------------------+-----------------------------+
|                           1 |                           0 |
+-----------------------------+-----------------------------+

Same problem with selects from tables containing empty rows.

How to repeat:
SELECT '' = CONCAT(CHAR(31),'ABC');
[28 Jan 2005 23:42] Jim Winstead 
This was a mistake in how string comparisons that require space-padding were done.
[1 Feb 2005 2:50] Jim Winstead 
Pushed to 4.1.
[3 Feb 2005 22:09] Paul DuBois 
Mentioned in 4.1.10 change notes.